(4-x)^2=5(2+x)

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Solution for (4-x)^2=5(2+x) equation: 



(4-x)^2=5(2+x)

We move all terms to the left:

(4-x)^2-(5(2+x))=0

We add all the numbers together, and all the variables

(-1x+4)^2-(5(x+2))=0



We calculate terms in parentheses: -(5(x+2)), so:

5(x+2)

We multiply parentheses

5x+10

Back to the equation:

-(5x+10)



We get rid of parentheses

(-1x+4)^2-5x-10=0

We add all the numbers together, and all the variables

-5x+(-1x+4)^2-10=0

We move all terms containing x to the left, all other terms to the right

-5x+(-1x+4)^2=10

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